(PHP 4, PHP 5, PHP 7, PHP 8)
is_resource — Finds whether a variable is a resource
value
The variable being evaluated.
Returns true
if value
is a resource,
false
otherwise.
Example #1 is_resource() example
<?php$handle = fopen("php://stdout", "w");if (is_resource($handle)) { echo '$handle is a resource';}?>
The above example will output:
$handle is a resource
Note:
is_resource() is not a strict type-checking method: it will return
false
ifvalue
is a resource variable that has been closed.